A simple random sample (SRS) of 125 is taken from a population with a 0.2 proportion of success. An independent SRS of 175 is taken from a population with a 0.9 proportion of success. What is the standard deviation of the sampling distribution for the difference in sample proportions?

A) 0.0424
B) 0.0497
C) 0.0018
D) 0.0245
E)None of the above

Respuesta :

Answer:

[tex]s= \sqrt{\frac{0.2(1-0.2)}{125} +\frac{0.9 (1-0.9)}{175}} =0.0424[/tex]

And the best option would be:

A) 0.0424

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

[tex]p_A[/tex] represent the real population proportion for the first case A

[tex] p_A =0.2[/tex] represent the proportion for case A

[tex]n_A=125[/tex] is the sample size selected for A

[tex]p_B[/tex] represent the real population proportion for case B

[tex]\hat p_B =0.9[/tex] represent the estimated proportion for case B

[tex]n_B=175[/tex] is the sample size required for case B

[tex]z[/tex] represent the critical value for the margin of error  

Solution to the problem

The population individual proportion have the following distribution  

[tex]p \sim N(p,\sqrt{\frac{p(1-p)}{n}})[/tex]  

And the standard deviation for the difference of proportions woud be given by:

[tex] s= \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}[/tex]

And replacing we got:

[tex]s= \sqrt{\frac{0.2(1-0.2)}{125} +\frac{0.9 (1-0.9)}{175}} =0.0424[/tex]

And the best option would be:

A) 0.0424

The standard deviation of the sampling distribution for the difference in sample proportions is option A.  0.0424

Given information:

A simple random sample (SRS) of 125 is taken from a population with a 0.2 proportion of success. An independent SRS of 175 is taken from a population with a 0.9 proportion of success.

Calculation of the standard deviation:

[tex]= \sqrt{\frac{0.2(1-0.2)}{125} + \frac{0.9(1-0.9)}{175} }[/tex]

= 0.0424

Learn more about the sample here: https://brainly.com/question/19585705