Answer:
[tex]\\\\4 cm^2[/tex]
Explanation:
Given that:
a cat stands on a scale and finds its weight to be 4.0 kilograms.
thus; the Force F the cat exerted on the scale = 4.0 kg
If the weight exerted by all four of its paws on the scale is .25 kilograms per square centimeter
i.e the Pressure P exerted by all the four paws weighs = 0.25 kg/cm²
Then:
[tex]\frac{F}{A}= P[/tex]
[tex]\frac{4.0 \ kg}{A}= \frac{0.25 \ kg }{1 \ cm^2}\\\\\\\frac{4.0 \ kg}{A}= {0.25 \ kg/cm^2 }\\\\4.0 \ kg = 0.25 \ A \ \ kg/cm^2\\\\\\A = \frac{4 kg}{0.25 kg /cm^2 }\\\\A = 16 cm^2\\[/tex]
The total area of the cat's paws is = 16 cm^2
Since a cat have 4 paws; the determine the area of one of its paws in square centimeters; we have ⇒ [tex]\frac{16 \ cm^2}{4} = 4 \ cm^2[/tex]
