A hippo is dozing under water with only its small nostrils sticking out. It has a mass of 2500 kg and a volume of about 2.46 m3 after exhaling. The hippo is in a pool of fresh water, with a density of 1g/cm3. What is the buoyancy force on the hippo?

Respuesta :

Answer:

The buoyancy force on the hippo is 24108 N

Explanation:

Given;

mass of hippo, m = 2500 kg

volume of hippo, V = 2.46 m³

density of fresh water, ρ = 1g/cm³

The buoyancy force on the hippo, is calculated used the following formula;

[tex]F_B = mg*\frac{\rho _{fluid}}{\rho _{hippo}}[/tex]

density of hippo = mass / volume = 2500/2.46 = 1016.26 kg/m³

density of fluid = 1g/cm³ = 1000 kg/m³

[tex]F_B = mg*\frac{\rho _{fluid}}{\rho _{hippo}} \\\\F_B = 2500*9.8 *\frac{1000}{1016.26} = 24108 \ N[/tex]

Therefore, the buoyancy force on the hippo is 24108 N

fichoh

The bouyancy Force of the hippo using the bouyancy force relation is 24107.1 N.

Given the Parameters :

  • Density of water = 1 kg/m³

  • Mass of hippo = 2500 kg

  • Volume = 2.46 m³

The bouyancy Force is defined as, [tex]F_{B}[/tex] :

[tex]F_{B} = (mg) \times \frac{ρ_{fluid}}{ρ_{h}}[/tex]

Density of hippo = [tex]ρ_{h} = \frac{2500}{2.46}= 1016.3 kg/m³ [/tex]

Substituting values into the relation :

[tex]F_{B} = (2500 \times 9.8) \times \frac{1000}{1016.3}[/tex]

[tex]F_{B} = (24500) \times 0.9839614 = 24107.1 N [/tex]

Therefore, the bouyancy Force is 24107.1 N

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