Answer:
The distance between the tip of her nose from the center of the crystal ball is 14.3 cm.
Explanation:
Given that,
Charge, [tex]q=5\times 10^{-9}\ C[/tex]
The end of her nose experiences an electric field strengths of 2200 N/C
It is required to find the distance between the tip of her nose from the center of the crystal ball. The formula of the electric field is given by :
[tex]E=\dfrac{kq}{r^2}[/tex]
r is distance
[tex]r=\sqrt{\dfrac{kq}{E}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 5\times 10^{-9}}{2200}} \\\\r=0.143\ m\\\\r=14.3\ cm[/tex]
So, the distance between the tip of her nose from the center of the crystal ball is 14.3 cm.
