Respuesta :
Answer: The mass of [tex]NaCl[/tex] produced is, 149 grams.
Explanation : Given,
Mass of [tex]PbCl_2[/tex] = 354.2 g
Molar mass of [tex]PbCl_2[/tex] = 278 g/mol
Molar mass of [tex]NaCl[/tex] = 58.5 g/mol
First we have to calculate the moles of [tex]PbCl_2[/tex]
[tex]\text{Moles of }PbCl_2=\frac{\text{Given mass }PbCl_2}{\text{Molar mass }PbCl_2}[/tex]
[tex]\text{Moles of }PbCl_2=\frac{354.2g}{278g/mol}=1.27mol[/tex]
Now we have to calculate the moles of [tex]CaCl_2[/tex]
The balanced chemical equation is:
[tex]3PbCl_2+2Na_3PO_4\rightarrow 6NaCl+Pb_3(PO_4)_2[/tex]
From the reaction, we conclude that
As, 3 moles of [tex]PbCl_2[/tex] react to give 6 mole of [tex]NaCl[/tex]
So, 1.27 moles of [tex]PbCl_2[/tex] react to give [tex]\frac{6}{3}\times 1.27=2.54[/tex] mole of [tex]NaCl[/tex]
Now we have to calculate the mass of [tex]NaCl[/tex]
[tex]\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl[/tex]
[tex]\text{ Mass of }NaCl=(2.54moles)\times (58.5g/mole)=148.59g\approx 149g[/tex]
Therefore, the mass of [tex]NaCl[/tex] produced is, 149 grams.
