Answer:
The answer is: d. 0 V
Explanation:
The reactions are:
M⁺² + 2e⁻ = M
M = M⁺² + 2e⁻
According the Nernst expression:
[tex]E_{cell} =E_{o,cell} -\frac{0.059}{n} log\frac{[Red]}{[O*d]}[/tex]
Where
n = 2
Ecell = 0.118 V
[Red] = 1x10⁻⁵M
[O*d] = 0.1 M
Clearing Eo,cell:
[tex]E_{o,cell} =E_{cell} +\frac{0.059}{n} log\frac{[Red]}{[O*d]}=0.118+\frac{0.059}{2} log\frac{1x10^{-5} }{0.1} =0.118-0.118=0V[/tex]
