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A current I = 17 A is directed along the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.19 N/m acts on the conductor in the negative y-direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes. magnitude T direction.

Respuesta :

Answer:

The magnitude of magnetic field is 0.011 T in +z direction.

Explanation:

Given that,

Current, I = 17 A

The magnetic force per unit length, [tex]\dfrac{F}{l}=0.19\ N/m[/tex]

We need to find the magnitude and direction of the magnetic field in the region through which the current passes. The magnetic force acting on the conductor is given by :

[tex]F=ilB[/tex]

B is magnetic field

[tex]B=\dfrac{F}{il}\\\\B=\dfrac{0.19}{17}\\\\B=0.011\ T[/tex]

For direction,

[tex]\dfrac{F}{l}(-j)=i(+i) B[/tex]

The magnetic field is in +z direction. Hence, this is the required solution.

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