Respuesta :
Answer:
369 students have taken a course in either calculus or discrete mathematics
Step-by-step explanation:
I am going to build the Venn's diagram of these values.
I am going to say that:
A is the number of students who have taken a course in calculus.
B is the number of students who have taken a course in discrete mathematics.
We have that:
[tex]A = a + (A \cap B)[/tex]
In which a is the number of students who have taken a course in calculus but not in discrete mathematics and [tex]A \cap B[/tex] is the number of students who have taken a course in both calculus and discrete mathematics.
By the same logic, we have that:
[tex]B = b + (A \cap B)[/tex]
188 who have taken courses in both calculus and discrete mathematics.
This means that [tex]A \cap B = 188[/tex]
212 who have taken a course in discrete mathematics
This means that [tex]B = 212[/tex]
345 students at a college who have taken a course in calculus
This means that [tex]A = 345[/tex]
How many students have taken a course in either calculus or discrete mathematics
[tex](A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369[/tex]
369 students have taken a course in either calculus or discrete mathematics
Number of people choose either calculus or discrete math is 369
Given that;
Number of people choose calculus = 345
Number of people choose discrete math = 212
Number of people choose Calculus and discrete math = 188
Find:
Number of people choose either calculus or discrete math
Computation:
Number of people choose either calculus or discrete math = Number of people choose calculus + Number of people choose discrete math - Number of people choose Calculus and discrete math
Number of people choose either calculus or discrete math = 345 + 212 - 188
Number of people choose either calculus or discrete math = 369
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https://brainly.com/question/19591734?referrer=searchResults
