Answer:
Total sum at te end of 6 years=$ 73,138.97
Explanation:
The total sum in Lee's account at the end of year would be determined as follows:
FV= A × (1+r)^n
FV- Future sum?,
A- deposit amount ,
r- interest rate - 9%/2 = 4.5% per 6 months
n- number of years is 6
First deposit for 6 years
FV = 15,000× 1.045^(2×6)
= $25,438.22
Last 40,000 for 2 years
FV = 40,000 1.045^(2×2)
=47,700.74403
Total sum at the end of 6 years
= $25,438.22 + $47,700.74
=$ 73,138.97
