Answer:
The correct option is;
Jason's statement is correct. RST is the same orientation, shape, and size as ABC
Step-by-step explanation:
Here we have
ABC = (2, 1), (3, 3), (4, 1)
RST = (-4, -2), (-3, 0), (-2, -2)
Therefore the length of the sides are as follows
AB = [tex]\sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}[/tex]
AC = [tex]\sqrt{(2-4)^2+(1-1)^2} =2[/tex]
BC = [tex]\sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}[/tex]
For triangle SRT we have
RS = [tex]\sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}[/tex]
RT = [tex]\sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2[/tex]
ST = [tex]\sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}[/tex]
Therefore their dimensions are equal
However the side with length 2 occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST
That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.
