Answer:
See explanation below.
Step-by-step explanation:
[tex]\frac{x-2y}{4y}+\frac{4x-y}{4y}\\\\\mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\=\frac{x-2y+4x-y}{4y}\\\\\mathrm{Group\:like\:terms}:\\\\=\frac{x+4x-2y-y}{4y}\\\\\mathrm{Add\:similar\:elements:}\:x+4x=5x\\\\=\frac{5x-2y-y}{4y}\\\\\mathrm{Add\:similar\:elements:}\:-2y-y=-3y\\\\=\frac{5x-3y}{4y}[/tex]
