Respuesta :

Lightx

Answer:

3

Step-by-step explanation:

[tex] \sum 2n+1= \boxed{\big( \sum_{i=1} ^{4}2n \big) +1}[/tex]

And,

$ \sum (2i+1)= \sum (2i)+ \sum_{i=1} ^{4} (1) $

$=\sum_{i=1} ^{4}(2i) + 1+1+1+1 $

$=\boxed{\Big(\sum_{n=1} ^{4}(2n)\Big) +4}.... \text{Variable in Summation doesn't matter}$

Hence the difference is 3.

Ver imagen Lightx
sakshigupta4990

3 the difference between 4∑n=1 2n+1 and 4∑i=1 (2i+1) by induction sequence, method.

Hence the difference is 3.

What is an inductive type?

Mathematical Induction Proof

In the simplest case, the application of Mathematical Induction is that the sum of the first n odd positive integers is n2 – that is (1.) 1 + 3 + 5 + ⋯ + (2n − 1) = n2 for all positive integers n. Let F be a class of integers for which equation (1) holds.

The inductive definition of the induction sequence is given by giving the first term and the rules of how to get from the previous term to the next term. For example, the definition u1 = 1, un + 1 = 2un + 3 produces this sequence 1,5,13,29.

4 (Σ2n) +1 i=1 Σ2n+1= =

And,

Σ(2i + 1) = Σ(2i) + Σi_1(1)

= (2i)+1+1+1+1

4 Σ(2n)) ((2n))+4... Variable in Summati n=1

Hence the difference is 3.

Learn more about induction sequence at

https://brainly.com/question/27842309

#SPJ2

Ver imagen sakshigupta4990