Answer:
Refractive index of second material will be 1.41
Explanation:
It is given refractive index of first material, that is air [tex]n_1=1[/tex]
Angle of incidence = 41.1°
Angle of refraction from second material = 27.7°
We have to find the refractive index of second material.
Now from Snell's law [tex]n_1sini=n_2sinr[/tex]
[tex]1\times sin41.1=n_2\times sin27.7[/tex]
[tex]n_2=1.41[/tex]
So refractive index of second material will be equal to 1.4