1.998 ml of hydrogen gas volume is is required to react with 10.5 g of linolenic acid in this reaction.
Explanation:
Data given:
mass of linolenic acid is given = 10.5 grams
atomic mass of linoleinic acid = 278.43 grams/mole
volume of hydrogen required at STP = ?
Balance chemical reaction:
C18H30O2 + 3H2 --->C18H36O2
moles of linoleinic acid given = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]
putting the values in the equation:
moles of linoleinic acid = [tex]\frac{10.5}{278.43}[/tex]
= 0.037 moles
from the balanced equation:
1 mole of linoleinic acid reacts with 3 moles of hydrogen
so, 0.037 moles will react with x moles of hydrogen gas
[tex]\frac{1}{3}[/tex] = [tex]\frac{0.037}{x}[/tex]
x = 0.111 moles of water
volume or mass = atomic mass x number of moles
volume of hydrogen gas= 1.998 ml
