Answer:
Force required to pull is equal to 147.167 N
Explanation:
Torque is given [tex]\tau =40Nm[/tex]
Length of wrench l =30 cm = 0.3 m
Angle with wrench shaft [tex]\Theta =115^{\circ}[/tex]
We have to find the force with which you pull
Torque is equal to [tex]\tau =F\times lsin\Theta[/tex]
[tex]40=F\times 0.3\times sin115^{\circ}[/tex]
[tex]40=F\times 0.3\times 0.906[/tex]
F = 147.167 N
So force required to pull is equal to 147.167 N