Answer:
The maximum speed of the heart wall during the motion is 0.032 m/s
Explanation:
Given:
A = amplitude of vibration = 1.7 mm = 1.7x10⁻³m
f = frequency = 3 Hz
The angular velocity is:
[tex]w=2\pi f=2\pi *3=18.85Hz[/tex]
The maximum speed of the heart wall during the motion is equal to:
[tex]V=Aw=1.7x10^{-3} *18.85=0.032m/s[/tex]