Answer: instateneous center of zero velocity is 0.5m below G and velocities of A and B are 1.949m/s and 2.661m/s respectively.
Explanation:
Calculate the velocity with respect to G
(VBG)
VBG= w × BG
w= 4rad/s
BG= 0.3
VBG= 1.2m/sec
Velocity with respect to G
V AG= w × AG
V AG= 4 × 0.3
=1.2m/s
Use cosine rule to calculate absolute velocity of B
VB= √(VG) ^2+ (VBG)^2- 2(VG) (VBG) cos 110
VB= 2.661 m/s
VA= √(VG) ^2+ (V AG)^2- 2(VG) (V AG) cos 70
=1.949m/s
The point of the intersection of the perpendiculars drawn on VA, VB and VG from A, B and G respectively is instateneous centre of rotation.
GC= VG/w
Where VG is 2 m/sec and w is 4 rad/sec
GC=2/4
GC=0.5 (vertically below G)
Therefore, instateneous center of zero velocity is 0.5m below G and velocities of A and B are 1.949m/s and 2.661m/s respectively.
