Answer:
The fraction of kinetic energy lost in the collision is 0.25 .
Explanation:
We know , momentum will be conserved along x direction .
Therefore ,
[tex]0.248 \times 0+0.148\times 2.82 = 0.148\times 1.82 \times sin \ 25^{\circ} + 0.248\times v\\\\0.42=0.11+0.248 \times v\\\\v=1.25\ m/s[/tex]
Now , fraction lost in kinetic energy is :
[tex]Loss =\dfrac{K.E_i-K.E_f}{K.E_i}\\\\Loss=1-\dfrac{K.E_f}{K.E_i}\\\\Loss=1-\dfrac{\dfrac{0.148\times1.82^2}{2}+\dfrac{0.248 \times 1.25^2}{2}}{\dfrac{0.148\times 2.82^2}{2}+\dfrac{0.248\times 0^2}{2}}\\\\Loss =0.25[/tex]
Therefore , the fraction of kinetic energy lost in the collision is 0.25 .
