Answer:
The temperature differs in 25 degrees on the Celsius scale
Explanation:
The relationship between temperatures on the two scales is:
[tex] 9C = 5(F - 32) [/tex]
So, if the temperature recorded differed by 45, then the degrees on the Celsius scale can be calculated as follows:
[tex] F_{1} = \frac{9}{5}(C_{1} + 32) [/tex]
[tex] F_{2} = \frac{9}{5}(C_{2} + 32) [/tex]
Since F₂ - F₁ = 45, we have:
[tex] 45 = \frac{9}{5}(C_{2} + 32) - \frac{9}{5}(C_{1} + 32) [/tex]
[tex] 45 = \frac{9}{5}(C_{2} - C_{1} + 32 - 32) [/tex]
[tex] 45*\frac{5}{9} = C_{2} - C_{1} [/tex]
[tex]C_{2} - C_{1} = 25[/tex]
Therefore, the temperature extremes differ in 25 degrees on the Celsius scale.
I hope it helps you!
Answer:
The number of degrees the temperature extremes differ on the Celsius sale 25 °
Explanation:
Here we have
9 °C = 5(F-32)
On the day the temperature extremes recorded at the weather station differed by 45 ° F we then have
F₂ - F₁ = 45
F₂ = F₁ + 45
C₁ = 5(F₁-32)/9
C₂ = 5(F₂-32)/9
C₂ - C₁ = 5(F₂-32)/9 - 5(F₁-32)/9 = 5(F₂ - F₁)/9 = 5×45/9 = 25
Therefore, the number of degrees the temperature extremes differ on the Celsius sale = 25 °
That is the temperature on the Celsius scale increased by 25 °.
