The following data were obtained for the decomposition of N2O5 in CCl4 at 45 °C:
a. What is the order of the reaction with respect to (WRT) dinitrogen pentoxide?
b. What is the value of k?
c. What is the value of the half-life for the reaction in minutes?

Respuesta :

Answer:

a) [tex]k = \frac{ln\frac{C_0}{C_t} }{t} \\k = \frac{2.3}{t} log \frac{C_0}{C_t}[/tex]

b) [tex]6.31 * 10^{-4}[/tex]

c) [tex]1.094 * 10^{-3}[/tex]

Explanation:

Complete question

(min) 0         135          342           683             1693

c {M} 2.08 1.91          1.67                   1.35              0.57

Solution -

a) One this clear from the data provided and it is that rate of the reaction does not remain constant with time and hence it is not a zero order reaction. Thus, the equation for first order reaction is

[tex]k = \frac{ln\frac{C_0}{C_t} }{t} \\k = \frac{2.3}{t} log \frac{C_0}{C_t}[/tex]

b) Rate of reaction

Substituting the given values in above equation, we get -

[tex]k = \frac{2.3}{135} log \frac{2.08}{1.91} \\= 6.31 * 10^{-4}[/tex]

c) Value of the half-life for the reaction in minutes

[tex]t_{\frac{1}{2}} = \frac{0.69}{k}[/tex]

Substituting the given values in above equation, we get -

[tex]t_{\frac{1}{2}} = \frac{0.69}{6.31 * 10^{-31}} \\t_{\frac{1}{2}} = 1.094 * 10^{-3}[/tex]

per minute