In a coffee-cup calorimeter, 100.0 g of H2O and 100.0 mL of HCl are mixed. The HCl had an initial temperature of 44.6 oC and the water was originally at 24.6 oC. After the reaction, the temperature of both substances is 31.3 oC.
a. Was the reaction exothermic or endothermic?Explain.
b. Calculate how much heat the water lost or gained.

Respuesta :

Answer:

(a). For water the reaction is Endothermic & for HCL the reaction is Exothermic.

(b). The heat gain by the water is Q = 2.814 KJ

Explanation:

Given data

Mass of water = 100 gm

Initial temperature of HCL = 44.6 °c

Initial temperature of water = 24.6 °c

Final temperature of both substances = 31.3 °c

(a). For water the reaction is Endothermic because the temperature of water is increases during the mixing process.

But for HCL the reaction is Exothermic because the temperature of HCL is decreases.

(b). Heat gain by water is given by

[tex]Q = m C ( T_{2} - T_{1} )[/tex]

Q = 0.1 × 4.2 × (31.3 - 24.6)

Q = 2.814 KJ

Therefore the heat gain by the water is Q = 2.814 KJ

A. The reaction is endothermic for water and exothermic for HCl.

B. The heat gained by the water is 2803.28 J

A. Determination of the nature of the reaction.

Initial temperature of HCl = 44.6 °C

Initial temperature of water = 24.6 °C

Final temperature of both substance = 31.3 °C

From the above, we can conclude as follow:

  • The final temperature of the water is higher than it's initial temperature. This simply means that the reaction is endothermic for water.
  • The final temperature of the HCl is lesser than the initial temperature. This means that the reaction is exothermic for HCl.

B. Determination of the heat gained by the water.

  • Mass of water (M) = 100 g
  • Initial temperature (T₁) = 24.6 °C
  • Final temperature (T₂) = 31.3 °C
  • Change in temperature (ΔT) = T₂ – T₁ = 31.3 – 24.6 = 6.7 °C
  • Specific heat capacity of water (C) = 4.184 J/gºC
  • Heat gained (Q) =?

Q = MCΔT

Q = 100 × 4.184 × 6.7

Q = 2803.28 J

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