Answer:
[tex]z=-1.9[/tex]
Step-by-step explanation:
We have been that on a standardized exam, the scores are normally distributed with a mean of 200 and a standard deviation of 10. We are asked to find the z-score of a person who scored 181 on the exam.
We will use z-score formula to solve our given problem.
[tex]z=\frac{x-\mu}{\sigma}[/tex], where,
z = z-score,
x = Random sample score,
[tex]\mu[/tex] = Mean,
[tex]\sigma[/tex] = Standard deviation.
Upon substituting our given values in above formula, we will get:
[tex]z=\frac{181-200}{10}[/tex]
[tex]z=\frac{-19}{10}[/tex]
[tex]z=-1.9[/tex]
Therefore, the z-score of the person would be [tex]-1.9[/tex].
