Answer:
It doesn't lose any kinetic energy because the collision is elastic.
Explanation:
In an elastic collision, the momentum and kinetic energy are conserved
Answer:
The answer is: It loses 0.23 J
Explanation:
When the collision is elastic, both, momentum and kinetic energy is conserved, thus, the velocity is equal:
[tex]v_{1} =(\frac{m_{1}-m_{2}}{m_{1}+m_{2} } )u_{1}+\frac{2m_{2}u_{2}}{m_{1}+m_{2}}[/tex]
Where
m₁ = 620 g = 0.62 kg
m₂ = 320 g = 0.32 kg
u₁ = 2.1 m/s
u₂ = -3.8 m/s
Replacing:
[tex]v_{1} =(\frac{0.62-0.32}{0.62+0.32} )*2.1+\frac{2*0.32*(-3.8)}{0.62+0.32} =-1.917m/s[/tex]
The change of kinetic energy is:
[tex]E_{k} =\frac{1}{2} m*delta-v^{2} =\frac{1}{2} *0.62*((-1.917)^{2}-(2.1)^{2} )=-0.228=-0.23J[/tex]
The negative sign indicates a loss of energy
