Answer:
The distance of the screen from the slit is [tex]D= 11.62m[/tex]
Explanation:
From the question we are told that
The wavelength of the laser is [tex]\lambda = 681nm = \frac{681}{1*10^{-9}} = 681 *10^{-9}m[/tex]
The width of the slit is [tex]w_s = 1.1mm = \frac{1.1}{1000} =1.1 *10^{-3}m[/tex]
The number of dark fringe that is being considered [tex]n =12[/tex]
The distance to the center of the central maximum is [tex]d = 8.63\ cm = \frac{8.63}{100} = 8.63 * 10^ {-2}m[/tex]
The distance of the screen from the is mathematically represented as
[tex]D = \frac{d * w_s}{n* \lambda}[/tex]
Substituting values we have
[tex]D = \frac{8.63*10^{-2} * 1.1*10^{-3}}{12 * 681 *10^{-9}}[/tex]
[tex]D= 11.62m[/tex]
