[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{(x + 3)^2 = 49}\\\mathsf{(x + 3)(x + 3) = 49}\\\mathsf{x(x) + x(3) + 3(x) + 3(3) = 49}\\\mathsf{x(x) + 3(x) + 3(x) + 3(3) = 49}\\\mathsf{x^2 + 3x + 3x + 9 = 49}\\\mathsf{x^2 + 6x + 9 = 49}\\\\\large\text{SUBTRACT 49 to BOTH SIDES}\\\mathsf{x^2 + 6x + 9 - 49 = 49 - 49}\\\large\text{SIMPLIFY IT!}\\\\\large\text{FACTOR the LEFT SIDE}\\\mathsf{(x - 4)(x + 10) = 0}\\\\\large\text{SET the FACTORS TO EQUAL 0}\\\mathsf{x - 4 = 0 \ or\ x + 10 = 0}\\\large\text{SIMPLIFY IT!}\\\\\mathsf{x = 4\ or \ x = -10}[/tex]
[tex]\large\textsf{Therefore, your answer is: \huge\boxed{\mathsf{Option\ D. x = 4\ or\ x = -10}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
