Answer:
Answer is D. 98500 and 4000
Refer below.
Step-by-step explanation:
The average salary of a travel management professional is $98,500. Assume that the standard deviation of such salaries is $40,000. A random sample of 100 travel management professionals are selected, then the mean and standard deviation of the sampling mean is 98500 and 4000.
Answer:
c) 9850 and 4000
Step-by-step explanation:
Formula for calculating the standard deviation of the sampling mean = standard deviation/√n
Where n is the total number of sample = 100
Standard deviation of salaries = $40,000
Standard deviation of sampling mean = $40,000/√100
= $40,000/10
= $4,000
Similarly, mean deviation of the sampling mean = average salary/√n
Mean deviation of sampling mean = $98,500/√100
= $98,500/10
= $9,850
