At a certain vineyard it is found that each grape vine produces about 10 pounds of grapes in a season when about 600 vines are planted per acre. For each additional vine that is planted, the production of each vine decreases by about 1 percent. So the number of pounds of grapes produced per acre is modeled by
A(n) = (600 + n)(10 − 0.01n)
where n is the number of additional vines planted. Find the number of vines that should be planted to maximize grape production.

Respuesta :

Answer:

The number of additional vines to plant in order to maximize production  is 200

The total number of vines to maximize production is 800

Step-by-step explanation:

Notice that the expression for the number of pounds of grapes per acre  is in fact a quadratic expression in the variable "n":

[tex]A(n)=(600+n)(10-0.01n)\\A(n)= 6000-6n+10n-0.01n^2\\A(n) = 6000+4n-0.01n^2[/tex]

which is clearly associated with a parabola with arms pointing down (negative coefficient in the variable "n" squared). So by finding the vertex of the parabola, we can give the answer to what "n" (number of additional vines to plant).

Recall that the vertex of a parabola of the general shape: [tex]y=ax^2+bx+c[/tex] has an x-component defined by:

[tex]x_{vertex}=\frac{-b}{2a}[/tex]

then in our case, the "n" value for that vertex is: [tex]n_{vertex}= \frac{-4}{2(-0.01)} =200[/tex]

Then the additional number of vines to maximize grape production is 200

So the total should be: 600 + 200 =800

 To maximize the grapes production 800 vines should be planted.

Steps to maximize the production:

  •  Differentiate the function for the production with respect to the

          variable given in the function.

  •  Equate it to zero and find the value of the variable.

Given in the question,

Function representing the number of pounds of grapes produced per acre,

  • A(n) = (600 + n)(10 - 0.01n)

         Here, n = number of additional vines planted

Simplify the function,

A(n) = 600(10 - 0.01n) + n(10 - 0.01n)

       = 6000 - 6n + 10n - 0.01n²

       = -0.01n² + 4n + 6000

  • Differentiate the function with respect to variable 'n',

        A' = -0.02n + 4

  • Equate it to zero,

       A' = 0

       0.02n + 4 = 0

       n = 200

Additional vines to be planted = 200

Hence, total number of vines = 600 + 200 = 800

      Therefore, 800 vines should be planted to maximize the grape production.

Learn more about the maximization here,

https://brainly.com/question/5765993?referrer=searchResults