Answer:
The force must be applied to the small piston to raise the automobile [tex]F_S[/tex] = 932 N
Explanation:
Given data
Mass = 1900 kg
Force = m g
Force [tex]F_L[/tex] = 1900 × 9.81 = 18639 N
Area of larger Piston [tex]A_L[/tex] = 10 [tex]m^{2}[/tex]
Area of smaller Piston [tex]A_S[/tex] = 0.5 [tex]m^{2}[/tex]
Force on smaller piston = [tex]F_S[/tex]
From the equilibrium
Pressure on larger piston = Pressure on smaller piston
[tex]P_L = P_S[/tex]
[tex]\frac{F_S}{A_S} = \frac{F_L}{A_L}[/tex]
[tex]\frac{F_S}{0.5} = \frac{18639}{10}[/tex]
[tex]F_S[/tex] = 932 N
Therefore the force must be applied to the small piston to raise the automobile.
