Respuesta :
Answer:
17.15 m/s
Explanation:
Parameters given:
Magnetic field, B = 0.8 T
Mass of ball, m = 0.007 kg
Charge of ball, q = 0.005 C
The magnetic force acting on the charged ball due to the magnetic field is given as:
F = qvBsinθ
where v = velocity of the ball and θ = angle between the horizontal and the magnetic field = 90°
The force of the ball will be in the opposite direction but of equal magnitude:
[tex]F_b[/tex] = -qvBsin(90) = -qvB
To cancel out the effect of gravity, the magnetic force must be equal to the gravitational force acting on the ball:
F = mg
Therefore:
mg = -qvB
Solving for velocity, v, we have:
[tex]v = \frac{mg}{-qB}[/tex]
[tex]v = \frac{0.007 * 9.8}{-(-0.005) * 0.8}[/tex]
v = 17.15 m/s
The ball must be moving at a velocity of 17.15 m/s.
