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A canister of 2.00 moles of helium has a volume of 30.0 L and is at a temperature of 293 Kelvin. what is the pressure of this gas?
1. 19.5 kPa
2. 101.3 kPa
3. 162 kPa
4. 211 kPa​

Respuesta :

Neetoo

Answer:

P = 162 KPa

Explanation:

Given data:

Number of moles = 2 mol

Volume of gas = 30.0 L

Temperature of gas = 293 K

Pressure of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

P = nRT/V

P = 2 mol ×0.0821 atm.L/ mol.K  ×293 K/ 30.0 L

P = 48.11 atm.L/  30.0 L

P = 1.6 atm

atm to kelvin:

1.6×101 = 162 KPa

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