A wire along the z axis carries a current of 6.4 A in the z direction Find the magnitude and direction of the force exerted on an 8.0 cm long length of the wire by a uniform magnetic field with magnitude 0.50 T in the x direction

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Answer:

The magnetic force will be 0.256 N in +y direction.                                          

Explanation:

It is given that, a wire along the z axis carries a current of 6.4 A in the z direction. Length of the wire is 8 cm. It is placed in uniform magnetic field with magnitude 0.50 T in the x direction.

The magnetic force in terms of length of wire is given by :

[tex]F=I(L\times B)\\\\F=ILB\\\\F=6.4\times 0.08\times 0.5\\\\F=0.256\ N[/tex]

For direction,

[tex]F=I k(L\times Bi)\\\\F=Fj[/tex]

So, the magnetic force will be 0.256 N in +y direction.