Answer:
The magnetic force will be 0.256 N in +y direction.
Explanation:
It is given that, a wire along the z axis carries a current of 6.4 A in the z direction. Length of the wire is 8 cm. It is placed in uniform magnetic field with magnitude 0.50 T in the x direction.
The magnetic force in terms of length of wire is given by :
[tex]F=I(L\times B)\\\\F=ILB\\\\F=6.4\times 0.08\times 0.5\\\\F=0.256\ N[/tex]
For direction,
[tex]F=I k(L\times Bi)\\\\F=Fj[/tex]
So, the magnetic force will be 0.256 N in +y direction.