Answer:
The work required is W = 20.2 BTU per lbm
Explanation:
The value of entropy & enthalpy at initial conditions are
[tex]h_{1}[/tex] = 103.1
S = 0.225
Final enthalpy
[tex]h_{2}[/tex] = 123.3
Therefore work done
W = [tex]h_{1}[/tex] - [tex]h_{2}[/tex]
W = 103.1 - 123.3
W = - 20.2 BTU per lbm
Therefore the work required is W = 20.2 BTU per lbm
