You have a circuit with a 50 Ω , a 100 Ω , and a 150 Ω - resistor connected in series. (a) Rank the current through them from highest to lowest. (b) Rank the potential difference across them from highest to lowest. Explain your rankings.

(a) A circuit has 50 Ω, a 100Ω and a 150 Ω resistor are connected in series. We know that in series combination, current through each resistor is same. So, current through a 50 Ω, a 100Ω and a 150 Ω resistor is same.

(b) Ohm's law of given by :

V = I R

V is potential difference. As I is same, so, the resistor having highest resistance will have highest potential difference. So,

[tex]V_3>V_2>V_1[/tex].

Hence, this is the required solution.

andromache andromache · Answer 2 · 2022-02-19T06:22:37+01:00

a. The current should be the same

b. The ranking should be [tex]V_3>V_2>V_1[/tex]

Ohm's law:

a. A circuit that comprises of 50 Ω, a 100Ω, and 150 Ω . These resistors are connected in series. In the case of series combination, the current via each resistor should be similar. Thus, current via a 50 Ω, a 100Ω, and a 150 Ω resistor is the same.

b.

According to the above law,

we know that

V = I R

here V represents potential difference. Since I is the same, due to this, the resistor has the highest resistance that contains highest potential difference. So, the ranking should be [tex]V_3>V_2>V_1[/tex]

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