Respuesta :
Answer:
The time period of the object is 0.2 seconds.
Explanation:
An object is oscillating as depicted in the expression below :
[tex]x(t)=\sin (\pi 10t)[/tex] ........(1)
The general equation is given by :
[tex]x(t)=A\ \sin \omega t[/tex] .......(2)
Comparing equation (1) and (2) we get :
[tex]\omega=10\ \pi[/tex]
The relation between angular frequency and time period is given by :
[tex]T=\dfrac{2\pi }{\omega}\\\\T=\dfrac{2\pi }{10\pi}[/tex]
T = 0.2 seconds
So, the time period of the object is 0.2 seconds.
The time period of the object should be considered as the 0.2 seconds when the time t should be considered as the units of seconds.
Calculation of the time period:
Since
An object when oscillating should be
x(t) = sin(π10t).............(1)
And, the general equation should be
x(t) = A sin wt........(2)
Now after comparing it
w = 10 π
So,
T = 2π/w
= 2π / 10 π
= 0.2 seconds
hence, The time period of the object should be considered as the 0.2 seconds.
Learn more about an oscillation here: https://brainly.com/question/13686167?referrer=searchResults
