A GAS SAMPLE HAS A TEMPERATURE OF 18 CELSIUS WITH AN UNKNOWN VOLUME. THE SAME GAS HAS A VOLUME OF 436 ML WHEN THE TEMPERATURE IS 91 CELSIUS WITH NO CHANGE IN THE PRESSURE AND AMOUNT OF GAS

Respuesta :

Answer : The unknown volume will be, 348.6 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.

[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.

We are given:

[tex]V_1=?\\T_1=18^oC=(18+273)K=291K\\V_2=436mL\\T_2=91^oC=(91+273)K=364K[/tex]

Now put all the given values in above equation, we get:

[tex]\frac{V_1}{291K}=\frac{436mL}{364K}\\\\V_1=348.6mL[/tex]

Therefore, the unknown volume will be, 348.6 mL