Answer:
1.88cm
Explanation:
F = 210 N/m
L = 0.38m
I₁ = I₂ = I = 1400A
r = ?
μ₀ = 4π * 10⁻⁷ N/A²
From Bio-Savart law,
F/L = μ₀I₁I₂ / 4πr²
but I₁ = I₂ = I
(210 / 0.38) = (4π * 10⁻⁷ * 1400²) / 4πr²
552.63 = (1*10⁻⁷ * 1960000) / r²
552.63r² = 0.196
r² = 0.196 / 552.63
r² = 3.546*10⁻⁴
r = √(3.546*10⁻⁴)
r = 0.0188m = 1.88cm
Answer:
The separation between the rods is 0.024 m
Explanation:
Given:
L = length of the rods = 0.38 m
k = spring constant = 210 N/m
I = current = 1400 A
Δx = 3 cm = 0.03 m
The separation between the rods can be get from:
[tex]IL(\frac{\mu I}{2\pi r} )=-k*delta-x\\r=\frac{\mu I^{2} L}{2\pi k*delta-x} =\frac{4\pi x10^{-7}*1400^{2}*0.38 }{2\pi *210*0.03} =0.024m[/tex]
