Answer: Molarity of the prepared solution is [tex]1.75\times 10^{-3}mole/L[/tex]
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]V_s[/tex] = volume of solution in ml = 500 ml
moles of solute =[tex]\frac{\text {given mass}}{\text {molar mass}}=\frac{0.258g}{294.19g/mol}=8.77\times 10^{-4}mol[/tex]
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{8.77\times 10^{-4}moles\times 1000}{500ml}=1.75\times 10^{-3}mole/L[/tex]
Thus molarity of the prepared solution is [tex]1.75\times 10^{-3}mole/L[/tex]
