Answer:
The probability that a part is good given that it passed the inspection machine is P=0.978.
Step-by-step explanation:
As the inspection machine detect and discard any part that is completely defective, only the good and partially defective parts passed this inspection.
Then, if we have:
Probability of being a good part P(G)=0.90
Probability of being a patially defective part P(P)=0.02
Probability of being a completely defective part P(D)=0.08.
Probability of passing the inspection machine = 1-P(D)=1-0.08=0.92
Then, the probability of having a good part, given that it passed the inspection machine is:
[tex]P(G|Pass)=P(G)/P(Pass)=0.90/0.92=0.978[/tex]
