Answer:
160.296 N
Explanation:
At the bottom of the circle,
Applying,
Tension = centrifugal force- weight of the ball
T = mv²/r-mg.......................... Equation 1
Where T = tension in the cable, m = mass of the ball, v = speed of the ball, r = radius of the circle, g = acceleration due to gravity
Given: m = 1.07 kg, v = 13.9 m/s, r = 1.38 m, g = 9.8 m/s²
Substitute into equation 1
T = (1.07(13.9²)/1.38)+[1.07(9.8)]
T = (1.07(193.21)/1.38)+(10.486)
T = (206.7347/1.38)+(10.486)
T = 149.81+10.486
T =160.296 N
Hence the tension in the cable when the mass is at the bottom of the circle = 160.296 N