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Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation:
C6H12O6(aq) + 6O2(g) ⟶ 6CO2(g) + 6H2O(l)
1) Calculate the number of grams of oxygen required to convert 23.0 g of glucose to CO2 and H2O.
2) Calculate the number of grams of CO2 produced.

Respuesta :

sebassandin

Answer:

1) [tex]m_{O_2}=24.5gO_2[/tex]

2) [tex]m_{CO_2}=33.7gCO_2[/tex]

Explanation:

Hello,

1) In this case, by considering the given reaction, starting by 23.0 g of glucose, the grams of oxygen by stoichiometry result:

[tex]m_{O_2}=23.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molO_2}{1molC_6H_{12}O_6}*\frac{32gO_2}{1molO_2} \\m_{O_2}=24.5gO_2[/tex]

2), Now, by means of also stoichiometry, the grams of carbon dioxide that are produced result:

[tex]m_{CO_2}=23.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molCO_2}{1molC_6H_{12}O_6}*\frac{44gCO_2}{1molCO_2}\\m_{CO_2}=33.7gCO_2[/tex]

Best regards.

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