Respuesta :
Answer:
The p-value is greater than 0.10.
Step-by-step explanation:
The dependent t-test (also known as the paired t-test or paired-samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.
In this case, the teacher is performing a paired t-test to check whether there is any improvement in the scores after using the new unit on fractions.
The hypothesis can be defined as:
H₀: There is no improvement in the scores after using the new unit on fractions, i,e, μₓ = 0.
Hₐ: There is an improvement in the scores after using the new unit on fractions, i,e, μₓ > 0.
Here the variable, μₓ is defined as the difference between the the scores on the post-test and pre-test, i.e.
μₓ = post-test - pre-test
It is provided that the test statistic value is, t = -0.15.
A sample of n = 5 students were selected.
Compute the p-value of the test as follows:
[tex]p-value=P(t_{n-1}>t)\\[/tex]
[tex]=P(t_{4}>-0.15)\\=P(t_{4}<0.15)\\=0.444[/tex]
*Use a t-table.
Thus, the p-value is greater than 0.10.
The required value of p is greater than 0.10.
Given that,
She has five randomly selected students take a pre-test and a post test on the material.
The scores are out of 20.
We have to determine,
The test statistic is -0.15. What would be the p-value.
According to the question,
The teacher is performing a paired t-test to check whether there is any improvement in the scores after using the new unit on fractions.
The hypothesis can be defined as:
H₀: There is no improvement in the scores after using the new unit on fractions, i.e. μₓ = 0.
Hₐ: There is an improvement in the scores after using the new unit on fractions, i.e., μₓ > 0.
The variable, μₓ is defined as the difference between the the scores on the post-test and pre-test given as;
μₓ = post-test - pre-test
This is provided that the test statistic value is, t = -0.15.
A sample of n = 5 students were selected.
The p-value of the test is given by,
[tex]= p(t_n_-_1 >t)\\\\\= p (t_5_-_1>-0.15_)\\\\= p(t_4<0.15)\\\\= 0.444[/tex]
By using t- table Thus, the p-value is greater than 0.10 .
Hence, The required value of p is greater than 0.10.
To know more about Hypothesis click the link given below.
https://brainly.com/question/20165896
