Answer:
The hypothesis should be retained
Step-by-step explanation:
We are given:
N= 16
n = 4
[tex]SS_B_G = 24 [/tex]
[tex] SS_E = 48 [/tex]
Level of significance, a = 0.05
From the given data, our ANOVA table will be:
[tex]----Source: Between---- Residual---[/tex]
[tex]------DF:n-1=> 4-1=3------N-n=>16-4=12[/tex]
[tex]------SS: SS_B_G = 24---- SS_E =48[/tex]
[tex]----MS: MS_B_G = 8----MS_E=48/12=4[/tex]
Note: proper ANOVA table is attached
The statistic will be written as:
[tex] TS = \frac{MS_B_G}{MS_E} ~ F_n_-_1, _N_-_n [/tex]
T = 8/4 = 2
Therefore
[tex] F_n_-_1, _N_-_n, _a [/tex]
[tex]=> F_3,_1_2,_ 0_._0_0_5 = 3.490[/tex]
The hypothesis should be retained, because we no know that the statistic is in the acceptance area.
