Answer:
a) 2.5 shots
b) 59.4 shots
c) 4.87 shots
Step-by-step explanation:
Probability of making the shot = 0.6
Probability of missing the shot = 0.4
a) The expected number of shots until the player misses is given by:
[tex]E(X) = \frac{1}{P(X)}=\frac{1}{0.4} \\E(X) = 2.5\ shots[/tex]
The expected number of shots until the first miss is 2.5
b) The expected number of shots made in 99 attempts is:
[tex]E=99*0.6\\E=59.4\ shots[/tex]
He is expected to make 59.4 shots
c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:
[tex]s=\sqrt{n*p*(1-p)}\\ s= 4.87\ shots[/tex]
The standard deviation is 4.87 shots.
