Respuesta :
Complete Question:
The five stars or star like objects are given below:
1) Newly formed [tex]0.09M_{sun}[/tex] star
2) [tex]0.065 M_{sun}[/tex] Protostar
3) [tex]0.9M_{sun}[/tex] white dwarf; single star(not binary)
4) 1[tex]M_{sun}[/tex] main sequence star,; single star(not binary)
5) 1.4[tex]M_{sun}[/tex] white dwarf; binary with a red giant companion
Answer:
Check below for the explanations
Explanation:
The lifetime of the star will be given by:
[tex]\tau = \tau_{sun} (\frac{M}{M_{sun} }) ^{-2.5}[/tex]
Lifetime of the sun, [tex]\tau_{sun} = 10^{10} years[/tex]
1) For the newly formed [tex]0.09M_{sun}[/tex] star
[tex]\tau = 10^{10} * (0.09) ^{-2.5}\\\tau = 4.11 * 10^{12} years[/tex]
The star is in the main sequence
2) [tex]0.065 M_{sun}[/tex] Protostar
[tex]\tau = 10^{10} * (0.065) ^{-2.5}\\\tau = 9.28 * 10^{12} years[/tex]
The star is a brown dwarf, it cannot fuse hydrogen at its core
3) [tex]0.9M_{sun}[/tex] white dwarf; single star(not binary)
[tex]\tau = 10^{10} * (0.9) ^{-2.5}\\\tau = 1.30 * 10^{12} years[/tex]
At this time, a lot of its initial radiation has been emitted and the temperature has become low. It is a cold white dwarf
4) 1[tex]M_{sun}[/tex] main sequence star,; single star(not binary)
[tex]\tau = 10^{10} * (1.0) ^{-2.5}\\\tau = 1 * 10^{10} years[/tex]
At this time, a lot of radiation will be emitted, the star is a hot white dwarf
5) 1.4[tex]M_{sun}[/tex] white dwarf; binary with a red giant companion
[tex]\tau = 10^{10} * (1.4) ^{-2.5}\\\tau = 4.31 * 10^{9} years[/tex]
At this time, it will continue to undergo a gravitational collapse from the nearest future, so It is a neutron star.
