Answer:
The ratio of the acceleration of the proton to that of the deuteron is 2
Explanation:
For a moving charge in magnetic field, the magnetic force is balanced by force due to its motion. So,
[tex]qvB=ma[/tex]
Acceleration of proton,
[tex]a_p=\dfrac{qvB}{m_p}[/tex] .........(1)
Acceleration of deuteron,
[tex]a_d=\dfrac{qvB}{m_d}[/tex] ..........(2)
Since, a deuteron has the same charge as the proton but has twice its mass.
Dividing equation (1) and (2) we get :
[tex]\dfrac{a_p}{a_d}=\dfrac{m_d}{m_p}[/tex]
[tex]m_d=2m_p[/tex]
[tex]\dfrac{a_p}{a_d}=\dfrac{2m_p}{m_p}\\\\\dfrac{a_p}{a_d}=2[/tex]
So, the ratio of the acceleration of the proton to that of the deuteron is 2. Hence, the correct option is (a).