Respuesta :
Using the Emperical rule:
68% lie with one one standard deviation:
16 + 1.7 , 16-1.7 = 17.7, 14.3
14.3 is part of the 68%.
The remaining 32% of the distribution is outside the range, with half being less than and half being greater than.
32/2 = 16
The probability of living loner than 14.3 Would be 16%
the probability of a gorilla living longer than 14.3 years is 83.9%
Given :
The lifespans of gorillas in a particular zoo are normally distributed
Mean is 16 years and standard deviation is 1.7 years
Empirical rule diagram is attached below
We need to find the probability of a gorilla living longer than 14.3
Lets find out 14.3 lies in which standard deviation on left or right
mean is 16
[tex]mean - standard \; deviation =16-1.7=14.3[/tex]
14.3 lies on first standard deviation on left of mean 16
So we find out the area that covers after 14.3
The area after 14.3 is [tex]34+34++13.5+2.4=83.9[/tex]
the probability of a gorilla living longer than 14.3 years is 83.9%
Learn more : brainly.com/question/14280851
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