The lifespans of gorillas in a particular zoo are normally distributed. The average gorilla lives 16 years; the
standard deviation is 1.7 years.
Use the empirical rule (68 - 95 - 99.7%) to estimate the probability of a gorilla living longer than 14.3
years.


Percent % pls

Respuesta :

Using the Emperical rule:

68% lie with one one standard deviation:

16 + 1.7 , 16-1.7 = 17.7, 14.3

14.3 is part of the 68%.

The remaining 32% of the distribution is outside the range, with half being less than and half being greater than.

32/2 = 16

The probability of living loner than 14.3 Would be 16%

the probability of a gorilla living longer than 14.3 years is 83.9%

Given :

The lifespans of gorillas in a particular zoo are normally distributed

Mean is 16 years  and standard deviation is 1.7 years

Empirical rule diagram is attached below

We need to find the probability of a gorilla living longer than 14.3

Lets find out 14.3 lies in which standard deviation on left  or right

mean is 16

[tex]mean - standard \; deviation =16-1.7=14.3[/tex]

14.3 lies on first standard deviation on left of mean 16

So we find out the area that covers after 14.3

The area after 14.3 is [tex]34+34++13.5+2.4=83.9[/tex]

the probability of a gorilla living longer than 14.3 years is 83.9%

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