Respuesta :
Answer:
0.0529mol/L
Explanation:
Step 1:
Data obtained from the question. This includes:
mass (m) = 3.24 g
Van 't Hoff factor (i) = 1 (since the solution is a non electrolyte)
Temperature (T) = 22°C
Volume (V) = 955 mL
Osmotic pressure (Π) = 973 torr
Molar concentration (M) =?
Step 2:
Conversion of the units of the variable to appropriate units. This is so vital because it will help us to obtain the desired result in the right unit.
For temperature:
We need to covert the temperature Fom celsius to Kelvin temperature. This is illustrated below:
K = °C + 273
K = 22°C + 273
K = 295K
For osmotic pressure:
We need to convert the osmotic pressure from torr to atm. This is illustrated below:
760torr = 1atm
Therefore, 973 torr = 973/760 = 1.28atm
Step 3:
Determination of the molar concentration. This is illustrated below:
i = 1
T= 295K
Π = 1.28
M =?
Gas constant (R) = 0.082atm.L/Kmol
Π = iMRT
1.28 = 1 x M x 0.082 x 295
Divide both side by 0.082 x 295
M = 1.28/ (0.082 x 295)
M = 0.0529mol/L
Therefore, the molar concentration of the solution is 0.0529mol/L
Answer:
The molar concentration of this solution is 0.0529 mol/L
Explanation:
Step 1: Data given
Mass of a nonelectrolyte solute = 3.24 grams
Volume of solution = 955 mL = 0.955 L
Temperature = 22 °C = 295 K
Osmotic pressure = 973 torr = 973 /760 = 1.28026 atm
Step 2: Calculate the molar concentration
π = i*C*R*T
⇒with π = the osmoti pressure = 1.28026 atm
⇒with i = the van't Hoff factor for a nonelectrolyte = 1
⇒with C = the molar concentration = TO BE DETERMINED
⇒with R = the gas constant = 0.08206 L*atm/mol*K
⇒with T = the temperature = 22 °C = 295 K
1.28026 = 1 * C * 0.08206 * 295
C = 1.28026 / (0.08206 * 295)
C = 0.0529 mol / L
The molar concentration of this solution is 0.0529 mol/L
