Respuesta :
Answer:
m = 8.7917 g
Explanation:
This reaction to form the Acetylsalicylic acid, is the following:
C4H6O3 + C7H6O3 --------> C9H8O4 + C2H4O2
Now, the problem already stated that the limiting reactant is the acetic anhydride (C4H6O3), and it's a 1:1 mole ratio, so this means that the moles of acetic anhydride reacting will be the moles of acetylsalicylic acid formed. We have the volume of the anhydride and density, let's calculate the mass, and then, the moles:
d = m/V ------> m = d * V
m = 1.082 * 4.6 = 4.9772 g
The molar mass of C4H6O3 reported is 102.09 g/mol so the moles are:
moles = 4.9772 / 102.09 = 0.0488 moles
As the mole ratio is 1:1 these moles are the same moles of the acid so:
moles Ac Acid = 0.0488 moles
The reported molar mass of the acid is 180.158 g/mol, then the mass:
m = 0.0488 * 180.158 = 8.7917 g
m = 8.7917 g
This is the theorical yield for the reaction
Answer:
We can make 8.8 grams of acetylsalicylic acid
Explanation:
Step 1: Data given
acetic anhydride = C4H6O3
Volume of acetic anhydride = 4.6 mL = 0.0046 L
Density acetic anhydride = 1.082 g/mL
acetylsalicylic acid = C9H8O4
Step 2: The balanced equation
C4H6O3 + C7H6O3 → C9H8O4 + C2H4O2
Step 3: Calculate mass acetic anhydride
Mass = density * volume
MAss acetic anhydride = 1.082 g/mL * 4.6 grams
Mass acetic anhydride = 4.9772 grams
Step 4: Calculate moles acetic anhydride
Moles = mass / molar mass
Moles acetic anhydride = 4.9772 grams / 102.09 g/mol
Moles acetic anhydride = 0.04875 moles
Step 5: Calculate moles acetylsalicylic acid
For 1 mol C4H6O3 we need 1 mol C7H6O3 to produce 1 mol C9H8O4 and 1 mol C2H4O2
For 0.04875 moles C4H6O3 we'll have 0.04875 moles C9H8O4
Step 6: Calculate mass acetylsalicylic acid
Mass acetylsalicylic acid = moles acetylsalicylic acid / molar mass acetylsalicylic acid
Mass acetylsalicylic acid = 0.04875 moles * 180.158 g/mol
Mass acetylsalicylic acid = 8.8 grams
We can make 8.8 grams of acetylsalicylic acid
