Answer:
The final pressure of the gas inside the bottle is reduces to half of its initial value.
Explanation:
According to Gay-Lussac’s law the pressure of the gas is directly proportional to the temperature of the gas.
P ∝ T
[tex]\frac{P_1}{P_2} = \frac{T_1}{T_2}[/tex]
Given that bottle was cooled to half of its original temperature means
[tex]T_2 = \frac{1}{2} T_1[/tex]
[tex]\frac{T_1}{T_2} = 2[/tex]
[tex]\frac{P_1}{P_2} = 2[/tex]
[tex]P_2 = \frac{1}{2} P_1[/tex]
Therefore the final pressure of the gas inside the bottle is reduces to half of its initial value.
The pressure of the gas inside the sealed bottle will be reduced to half of
its initial value.
Gay - Lussac's law states that the pressure is directly proportional to the temperature of a gas.
P ∝ T
P1 = T1
P2 T2
Since we were told that it was cooled to half of its original temperature then it means
T2 = 1/2 T1
T1/T2 = 2
P1/P2 = 2
P2 = 1/2 P1
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