Answer:
21.6 x 10^8 N
Explanation:
F = k q1 q2 /r^2
= 9 x 10^9 x 3 x 2 / 5^2
= 21.6 x 10^8 N
The electrostatic force between a 3C charge and a 2C charge is 2.16×10⁹N.
Given information:
Two charges are given such that:
q = 2C
Q = 3C
separated by the distance, R = 5m
According to Coulomb's Law, the electrostatic force between two charged particles q and Q separated by a distance R is given by:
[tex]F=\frac{1}{4\pi\epsilon_0}\frac{qQ}{R^2}\\\\F=9\times10^9\times\frac{2\times3}{5^2}[/tex]
F = 2.16 × 10⁹ N
So, the two given charges exert a force of 2.16 × 10⁹ N on each other.
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